Vandoorne third for Mercedes as Sam Bird wins FE season opener!
by Adam NewtonSam Bird has won the first race of Formula E season six in Saudi Arabia with a terrific drive from fifth on the grid. Mercedes' EQ FE had a superb start to life in the all-electric series as they qualified second and third with Stoffel Vandoorne and Nyck De Vries, with Vandoorne coming home third for a debut podium.
Britain's Alexander Sims was on pole and led from the start, but was pushed wide by Belgian Vandoorne, allowing Bird through to take his ninth Formula E win, keeping up his streak of taking a victory in every season.
Andre Lotterer came home second on Porsche's debut, ahead of Vandoorne, with his Mercedes teammate De Vries slipping back to sixth. Sims fell down to eighth before the chequered flag.
It was a nightmare start to the season for reigning two-time champion Jean-Eric Vergne, who was forced to retire from the race.


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Card Title
Projected revenue
Values include taxes | USD
3 of 15
21.83
K
14.52%
Q1, 2018
Table card
3 of 10
| Name |
Country |
Price |
Status |
| Banana |
India |
5 EUR |
Available
|
| Pineapple |
Mexico |
2 EUR |
Out of stock
|
| Orange |
Spain |
6 EUR |
Temporary unavailable
|
Card Title
Card Subtitle
3 of 10
-
item 1
-
item 2
-
item 3
-
item 4
Card Title
Card Subtitle
3 of 10
-
item 1
-
item 2
-
item 3
-
item 4
-
item 5
Card Title
Table card
3 of 10
| Name |
Country |
Price |
Status |
| Banana |
India |
5 EUR |
Available
|
| Pineapple |
Mexico |
2 EUR |
Out of stock
|
| Orange |
Spain |
6 EUR |
Temporary unavailable
|
Card Title
Card Subtitle
3 of 10
-
item 1
-
item 2
-
item 3
-
item 4
Card Title
Card Subtitle
3 of 10
-
item 1
-
item 2
-
item 3
-
item 4
-
item 5


Definition: One or more people make repairs to any part of a musical instrument
Explication: Repairing, adjusting, or cleaning musical instruments often involves taking apart some or all of the instrument, either to provide better access to some part of the instrument, or to replace or adjust a particular piece of the instrument. Common types of repairs/adjustments include replacing broken pieces of an instrument, tightening a knob to adjust a string (e.g. on a guitar or stringed instrument), applying oil to keys/valves (e.g. on a trumpet or saxophone).
Tools such as wrenches, pliers, and screwdrivers will usually be required for taking apart pieces of the instrument, and also for some adjustments that do not require taking the instrument apart, such as tightening strings.
Repairing woodwinds may involve replacing the pads that seal holes in the instrument when it is "fingered." Mechanical pivots of the mechanism are commonly cleaned and oiled.
Repairing brass instruments may involve various tools to remove dents, and these tools may include ball bearings of graduated sizes which are forced through the tubing. Cleaning with specialized brushes may be performed.
Repairing string instruments may involve woodworking tools and processes to fix the wooden body of the instrument.
Repairing a piano may involve specialized tools to adjust the keys, the structures that support the keys, the places where the keys pivot, and the various parts of the "action" that converts the keystroke into motion of the felt hammers that strike the strings.
Tuning a musical instrument is often part of repairing an instrument but not sufficient for evidence for repairing the instrument alone.


Berkeley DB: DbLog::stat
DbLog::stat
#include <db_cxx.h>
int
DbLog::stat(DB_LOG_STAT **spp, void *(*db_malloc)(size_t));
Description
The DbLog::stat function creates a statistical structure and copies
a pointer to it into the user-specified memory location.
Statistical structure are created in allocated memory.
If
db_malloc is non-NULL, it is called to allocate the memory,
otherwise, the library function malloc(3)) is used.
The function db_malloc must match the calling conventions of
the malloc(3)) library routine.
Regardless, the caller is responsible for deallocating the returned
memory.
To deallocate the returned memory, free each returned memory pointer;
pointers inside the memory do not need to be individually freed.
The log region statistics are stored in a structure of type DB_LOG_STAT.
The following DB_LOG_STAT fields will be filled in:
- u_int32_t st_magic;
- The magic number that identifies a file as a log file.
- u_int32_t st_version;
- The version of the log file type.
- u_int32_t st_refcnt;
- The number of references to the region.
- u_int32_t st_regsize;
- The size of the region.
- int st_mode;
- The mode of any created log files.
- u_int32_t st_lg_max;
- The maximum size of any individual file comprising the log.
- u_int32_t st_w_mbytes;
- The number of megabytes written to this log.
- u_int32_t st_w_bytes;
- The number of bytes over and above st_w_mbytes written to this log.
- u_int32_t st_wc_mbytes;
- The number of megabytes written to this log since the last checkpoint.
- u_int32_t st_wc_bytes;
- The number of bytes over and above st_wc_mbytes written to this log
since the last checkpoint.
- u_int32_t st_wcount;
- The number of times the log has been written to disk.
- u_int32_t st_scount;
- The number of times the log has been flushed to disk.
- u_int32_t st_cur_file;
- The current log file number.
- u_int32_t st_cur_offset;
- The byte offset in the current log file.
- u_int32_t st_region_wait;
- The number of times that a thread of control was forced to wait before
obtaining the region lock.
- u_int32_t st_region_nowait;
- The number of times that a thread of control was able to obtain
the region lock without waiting.
The DbLog::stat
method either returns errno or throws an exception that
encapsulates an errno on failure, and 0 on success.
Errors
If a fatal error occurs in Berkeley DB, the DbLog::stat method may fail and either
return DB_RUNRECOVERY or throw an exception encapsulating DB_RUNRECOVERY,
at which point all subsequent database calls will also fail in the same
way. Methods marked as returning errno will, by default, throw
an exception that encapsulates the error information. The default error
behavior can be changed, see DbException.
The DbLog::stat
method may fail and throw an exception
for any of the errors specified for the following Berkeley DB and C library
functions:
abort(3),
fcntl(3),
fprintf(3),
getpid(3),
malloc(3),
and
memset(3).
Class
DbLog
See Also
DbLog::archive,
DbLog::close,
DbLog::compare,
DbLog::file,
DbLog::flush,
DbLog::get,
DbLog::open,
DbLog::put,
DbLog::db_register,
DbLog::stat,
DbLog::unlink
and
DbLog::db_unregister.


Daily briefing: Base editors fix genomes one nucleotide at a time
A new class of CRISPR-based tools, an environmental DNA milestone and the integrity inspectors.
by Flora GrahamHello Nature readers, would you like to get this Briefing in your inbox free every day? Sign up here
Rare bird detected using DNA
For the first time, researchers have detected an endangered bird in the wild using traces of the genetic material it left behind. Environmental DNA gathered from waterholes in northern Australia revealed that Gouldian finches (Erythrura gouldiae) had visited the site in the previous two days. (Rangers also confirmed the species’ presence at the locations.) Compared with conventional methods that involve capturing or tracking, the technique is often safer for both animals and researchers, cheaper and, in some cases, more accurate and sensitive.
Reference: Endangered Species Research paper
Hong Kong protests close universities
Classes have been cancelled and research disrupted in the wake of violent clashes between police and protesters on the campuses of leading Hong Kong universities. Hong Kong Polytechnic University, City University of Hong Kong and the Chinese University of Hong Kong are the latest battlegrounds for protests that hinge on the extent of the territory’s independence from the mainland.
Australia addresses foreign interference
The Australian government has released new guidelines for universities to protect themselves against foreign interference. The move comes amid concerns over China’s influence on Australian campuses, and after major cybersecurity breaches at the Australian National University in Canberra. The guidelines require institutions to do due diligence on research collaborations with foreign partners and to introduce robust cybersafety strategies.
Features & opinion
The integrity inspectors
A handful of European institutions that have been hit by scandal are hiring integrity inspectors to vet researchers’ papers before they go to journals. Perhaps surprisingly, their researchers see the extra layer of checks as protective, not intrusive. “Because of the manuscript check, I sleep at night,” says biologist Björn von Eyss.
Fix genomes one nucleotide at a time
Base editors are a new class of CRISPR-based tools that excel at correcting single-site mutations. They are proteins that chemically change one DNA base to another without completely breaking the DNA backbone, making them more efficient and less error-prone than CRISPR–Cas9. Researchers hope that base editors might one day be used to treat human genetic diseases — if they can overcome important hurdles.
Rethink the roots of sexual behaviour
Considering how widespread same-sex sexual behaviour (SSB) is in animals across species and clades, it’s time to rethink some biased assumptions about its evolutionary origins and benefits, argue five biologists. “We aim to redefine the null hypothesis in studies of SSB,” they write. “Put simply, we are proposing a shift from asking ‘Why engage in SSB?’ to ‘Why not?’
Nature Ecology & Evolution | 31 min read
By the numbers
More than 1,500
The number of animal species in which same-sex sexual behaviour has been recorded, with a widespread distribution across most major clades.
Image of the week
A young jaguar (Panthera onca) in the Pantanal wetlands region in Brazil was spotted playing with a discarded plastic bottle by wildlife photographer Paul Goldstein, who described the sight as ‘distressing’. He added that the animal was probably attracted by the scent of the bottle, which would have floated downstream during the wet season.
See more of the month’s most compelling science images, selected by Nature’s photo team.
QUOTE OF THE DAY
“I recall a legendary chemistry professor who was inept at getting classroom demonstrations to work — but discussing what went wrong helped his students to thrive.”
It’s time to trust students to handle doubt and diversity in science, says philosopher of science Jerry Ravetz. (Nature)
Researchers responding to antibody engineer Esther Odek are sharing the weirdest things they’ve ever done in the name of science. (Mine is sending 64 million emails.)I’m glad that one of those emails reached you — please let me know what you think of it at briefing@nature.com.


How 'Anole.css' is structured
This page will eventually contain a detailed explanation of the
structure of 'anole.css', and the decisions that go into which
variables are used in each component.
-
Global Variables Come First
In `anole.css`, all global variables are listed first, for quick
access. Since these global variables affect just about
everything else, you can create an entire theme for Anole by
copying and changing just these.
-
Nested variables come next


Dr M says mulling Cabinet reshuffle, but insists no radical changes before Apec 2020
by BY RADZI RAZAKPETALING JAYA, Nov 20 — Prime Minister Tun Dr Mahathir Mohamad has admitted today that he will consider a Cabinet reshuffle, after several critics suggested that under-performing ministers led to Pakatan Harapan’s loss in Tanjung Piai.
Despite that, he assured the public that there will be no radical changes before Malaysia hosts the Asia Pacific Economic Cooperation (Apec) Summit scheduled in November next year, as such a drastic change will be problematic.
“The thing is, if we have a change midstream, it will be very confusing. It will create a lot of problems,” he said after chairing Parti Pribumi Bersatu Malaysia’s Supreme Council meeting here.
“But of course, if I’m sacked [then] I don’t know. But I think I need to be serious about this. What happens to me is not something important, but what happens to the country is very important.”
MORE TO COME


Nebula is part of Exploit Exercises, it covers a variety of simple and intermediate challenges that cover Linux privilege escalation, common scripting language issues, and file system race conditions.
This level requires you to find a Set User ID program that will run as the “flag00” account. You could also find this by carefully looking in top level directories in / for suspicious looking directories. Alternatively, look at the find man page.
In this first level, you have to find a file owned by flag00
with suid bit.
A single command can do the trick:
find / -user flag00 -perm /6000
Alternatively you can use -uid 999
where 999
is the user id of flag00
which can be found in /etc/passwd
.
This outputs the same result:
find / -user 999 -perm -u+s
/bin/.../flag00
is the key.
When you run it you become another user due to the suid.
Here is the POC:
The redirection is only used to avoid the errors triggered by the system when you try to read a forbidden directory.


Start Bootstrap
Home
(current)
Gallery
Videos
Audio
Contact Us
First Slide
This is a description for the third slide.
Secound Slide
This is a description for the third slide.
Third Slide
This is a description for the third slide.
Previous
Next


- Allows inheritance through a convenient .extend() method.
- Plays nicely with AMD (require.js for example) or CommonJS.
- Works either in the browser (one Class global variable) or in a Node environment through module.exports.
- File size: Less than 1 kb
Usage
If you'd like to use Class.js in a Node environment, you can install it using npm:
Example


Functional association of Nmi with Stat5 and Stat1 in IL-2 -and IFNgamma -mediated signaling.
Abstract
Using the coiled-coil region of Stat5b as the bait in a yeast two-hybrid screen, we identified the association of Nmi, a protein of unknown function previously reported as an N-Myc interactor. We further show that Nmi interacts with all STATs except Stat2. We evaluated two cytokine systems, IL-2 and IFNgamma, and demonstrate that Nmi augments STAT -mediated transcription in response to these cytokines. Interestingly, Nmi lacks an intrinsic transcriptional activation domain; instead, Nmi enhances the association of CBP/p300 coactivator proteins with Stat1 and Stat5, and together with CBP/p300 can augment IL-2- and IFNgamma-dependent transcription. Therefore, our data not only reveal that Nmi can potentiate STAT -dependent transcription, but also suggest that it can augment coactivator protein recruitment to at least some members of a group of sequence-specific transcription factors.


TAKE STEPS:
ROTATE:
SET SPEED:
STEP TO:
var stepper1 = new Stepper(); // set up a stepper wired with 4 pins (pin 2,3,4,5) on unit 1 stepper1.setup(1, 2, 3, 4, 5); // set speed stepper1.setSpeed(800); // 800 steps per second // rotate by steps stepper1.step(100); // take +100 steps stepper1.step(-100); // take -100 steps // step to a specified position stepper1.goto(1000); // go to position +1000 stepper1.goto(-1000); // to to position -1000 // stop stepper1.stop(); // get current stepper position stepper1.whenGetPosition = function(position) { document.getElementById("status").innerHTML = "present stepper position is " + position; }; stepper1.getPosition(); // set current stepper position as a specific value stepper1.setPosition(0); // set zero position
When the motor is running, the value of the stepper position will be updated by the steps rotated. The initialized position is 0, the value will increase after rotating forward, or decrease after rotating reverse. With a position counter maintained in the system, the allowed position value can range between -16777215 (-0xffffff) and 16777215 (0xffffff).
Stepper
setup(unit, pin1, pin2, pin3, pin4)
initialize a stepper object with four specified pins (pin1, pin2, pin3, pin4) on a specified unit.
return value: true if successful, otherwise false.
step(steps)
rotate the motor by the specified steps.
return value: true if successful, otherwise false.
goto(position)
set a number to the parameter as the target stepper position. The motor will rotate to the specified position.
return value: true if successful, otherwise false.
stop()
stop to rotate the motor.
return value: true if successful, otherwise false.
setSpeed(speed)
set a number of steps per second to the parameter for changing the motor rotating speed, return value: true if successful, otherwise false.
getSpeed()
request to get the current speed value of the stepper, an event callback whenGetSpeed() will be received later.
return value: the speed value, a number of steps per second.
setPosition(position)
set a number to the parameter as the current stepper position.
normally, the function is used for original zero position synchronizing in the motion control.
return value: true if successful, otherwise false.
getPosition()
request to get the current position of the stepper, an event callback whenGetPosition() will be received later.
return value: the stepper position value.
Return Value Note:
The function will return a value when your h5control program uses waitRsp mode, but no return value when uses nowaitRsp mode.
whenSetup(done)
receive the callback when setup done. parameter done is true if successful or false otherwise.
whenStep(steps)
receive the callback when the motor rotated by the specified steps.
whenGoto(position)
receive the callback when the motor is going to the specified target position.
whenStop()
receive the callback when stopped to rotate the motor.
whenSetSpeed(speed)
receive the callback when the stepper speed is set.
whenGetSpeed(speed)
receive the callback to to get the current speed value of the stepper after called function getSpeed().
whenSetPosition(position)
receive the callback when the current stepper position is set.
whenGetPosition(position)
receive the callback to to get the current stepper position after called function getPosition().


Settings changes will only take effect are pages are reloaded.
d20pfSRD bestiary
Archives of Nethys bestiary
Paizo PRD bestiary


Security Center
问题描述 :
Recently, wyh had learned a lot of knowledge about attack others’ computers. Now, if he has a way to access someone’s computer, the computers those connected directly or indirectly will suddenly be broken. To avoid it happening, the government set several computers with “Security Center”. These computers can prevent wyh’s attack. So they are called anti-wyhs. What’s more, anti-wyhs can protect the computers those connect to them directly or indirectly from wyh’s dreadful attack. But anti-wyhs can’t connect to a computer indirectly through wyh’s computer.
Now, the government asks you how many computers have been attacked.
输入:
The input will start with a line giving the number of test cases, T.
The first line of each case contains three integers n (0<n<20000), m (0<m<50000) and c(0<=c<=n-1) meaning the number of the computers including wyh’s, the number of those computers connect directly and the number of anti-wyhs. The second line contains c+1 integers. The first integer is the ID number of wyh’s computer. The following integers are the ID numbers of anti-wyhs. The ID number is numbered from 0 to n-1. Then m lines follow. Each line contain two integers x, y. This means that the computer x and y are connected directly.
The first line of each case contains three integers n (0<n<20000), m (0<m<50000) and c(0<=c<=n-1) meaning the number of the computers including wyh’s, the number of those computers connect directly and the number of anti-wyhs. The second line contains c+1 integers. The first integer is the ID number of wyh’s computer. The following integers are the ID numbers of anti-wyhs. The ID number is numbered from 0 to n-1. Then m lines follow. Each line contain two integers x, y. This means that the computer x and y are connected directly.
Note, if computer x connects to computer y, computer y also can connect to computer x.
输出:
The input will start with a line giving the number of test cases, T.
The first line of each case contains three integers n (0<n<20000), m (0<m<50000) and c(0<=c<=n-1) meaning the number of the computers including wyh’s, the number of those computers connect directly and the number of anti-wyhs. The second line contains c+1 integers. The first integer is the ID number of wyh’s computer. The following integers are the ID numbers of anti-wyhs. The ID number is numbered from 0 to n-1. Then m lines follow. Each line contain two integers x, y. This means that the computer x and y are connected directly.
The first line of each case contains three integers n (0<n<20000), m (0<m<50000) and c(0<=c<=n-1) meaning the number of the computers including wyh’s, the number of those computers connect directly and the number of anti-wyhs. The second line contains c+1 integers. The first integer is the ID number of wyh’s computer. The following integers are the ID numbers of anti-wyhs. The ID number is numbered from 0 to n-1. Then m lines follow. Each line contain two integers x, y. This means that the computer x and y are connected directly.
Note, if computer x connects to computer y, computer y also can connect to computer x.
样例输入:
1 4 3 2 0 2 3 0 1 0 2 1 2
样例输出:
0
#include<stdio.h> #include<string.h> #include<string> #include<iostream> #include<queue> #include<vector> #define MAX 22222 using namespace std; vector<int>vt[MAX]; int vis[MAX]; int a; int d[MAX]; int BFS(int n){ queue<int> q; q.push(n); int cnt=0; while(!q.empty()){ int now=q.front(); for(int i=0;i<vt[now].size();i++){ int to=vt[now][i]; if(vis[to]==0){ vis[to]=1; cnt++; q.push(to); } } q.pop(); } return cnt; } int main(){ int T; scanf("%d",&T); while(T--){ memset(vis,0,sizeof(vis)); int n,m,c; scanf("%d%d%d",&n,&m,&c); scanf("%d",&a); for(int i=0;i<n;i++)vt[i].clear(); for(int i=0;i<c;i++){ scanf("%d",&d[i]); } for(int i=0;i<m;i++){ int u,v; scanf("%d%d",&u,&v); vt[u].push_back(v); vt[v].push_back(u); } vis[a]=1; for(int i=0;i<c;i++){ vis[d[i]]=1; BFS(d[i]); } printf("%d\n",BFS(a)); } }
(adsbygoogle = window.adsbygoogle || []).push({});
快点出国语版
其实国内大部分公司对算法都不够重视。特别是中小型公司老板根本都不懂技术，也不懂什么是算法，从而也不要求程序员懂什么算法，做程序从来不考虑性能问题，只要页面能显示出来就是好程序，这是国内的现状，很无奈。
信息不全
给力的文章，例子也非常好
第一个数表示数列的个数，5表示之后有5个数
/*
* =====================================================================================
*
* Filename: 1366.cc
*
* Description:
*
* Version: 1.0
* Created: 2014年01月06日 14时52分14秒
* Revision: none
* Compiler: gcc
*
* Author: Wenxian Ni (Hello World~<EMAIL_ADDRESS>* Organization: AMS/ICT
*
* =====================================================================================
*/
#include
#include
using namespace std;
int main()
{
stack st;
int n,i,j;
int test;
int a[100001];
int b[100001];
while(cin>>n)
{
for(i=1;i>a[i];
for(i=1;i>b[i];
//st.clear();
while(!st.empty())
st.pop();
i = 1;
j = 1;
while(in)
break;
}
while(!st.empty()&&st.top()==b[j])
{
st.pop();
j++;
}
}
if(st.empty())
cout<<"YES"<<endl;
else
cout<<"NO"<<endl;
}
return 0;
}
终于明白了递归和dp的关系，多谢分享！
编辑的时候有些不小心了
一开始就规定不相邻节点颜色相同，可能得不到最优解。我想个类似的算法，也不确定是否总能得到最优解：先着一个点，随机挑一个相邻点，着第二色，继续随机选一个点，但必须至少有一个边和已着点相邻，着上不同色，当然尽量不增加新色，直到完成。我还找不到反例验证他的错误。。希望LZ也帮想想, 有想法欢迎来邮件。谢谢
3，求得所有的为的总和sum—->所有数的总和
printf( "Not Possible" );—->printf("impossible");
对吗？
题目需要求解的是最小值，而且没有考虑可能存在环，比如
0 0 0 0 0
1 1 1 1 0
1 0 0 0 0
1 0 1 0 1
1 0 0 0 0
会陷入死循环
3，求得所有的为的总和sum—->所有数的总和
printf( "Not Possible" );—->printf("impossible");
对吗？
辛苦了，顶
受益匪浅！！
2的64次方是多少？ 这到底是在考什么啊


Click here to download this week's dataset as a CSV
Click here to download this week's dataset as a Hyper Extract
Data Storytelling and Dataviz Approach
For this week, I wanted to look at both the changes in fresh fruit consumption over time, as well as the ranking of each fruit by consumption. To accomplish the task of showing the rank of each fruit's consumption, I used small multiples with calculated fields for [Row] and [Column] being driven off of a RANK calculation. For the small multiples, I used a custom Shape palette, built from icons sourced from The Noun Project.
In addition to the shapes, I used several calculated fields to drive the text that is pertinent based on both the fruit, it's rank and the year selected by interacting with the bottom viz. Interacting with the bottom viz, by clicking on a year, will re-order the fruits in the top viz based on their rank for the selected year, and updating the stats on consumption appropriately.
The bottom viz is a waterfall chart that shows changes in fruit consumption by year. This is accomplished using a Gannt chart, with multiple calculated fields to make the size and color look correct. Additionally, to provide some clarity regarding the direction of the waterfall chart - which may be unfamiliar to some people - I used a dual axis chart with custom arrow shapes to indicate the direction of the waterfall. Additionally, the same calculated field that drives the shape is also responsible for the color.
I wanted the viz to be completely interactive, so clicking on a fruit in the top viz filters the bottom to show changes in consumption for the selected fruit, and clicking on a year in the bottom viz filters the small multiples above to show the rank of each fruit by the chosen year. Overall, a pretty straightforward viz.
If you'd like to see what you can come up with, publish your work to Tableau Public, and Twitter with the hashtag #ThrowbackThursday, tagging @TThrowbackThurs. We'd really love to see what you can come up with!
Data Source
The dataset this week was sourced from the USDA Fruit and Tree Nut Yearbook. Please be sure to cite the source on your viz.


OpenClover @CORE_RELEASE_NUM@ Release Notes
Release date: @BUILD_DATE@
Documentation
For information about installing, configuring and using OpenClover please consult the documentation.
License
OpenClover is licensed under the Apache 2.0 License.
Change Log
Please see the release notes online at release notes.


Columbus’s bargain
问题描述 :
Because the ships are not large enough and there are seldom harbors in his route, Columbus had to buy food and other necessary things from savages. Gold coins were the most popular currency in the world at that time and savages also accept them. Columbus wanted to buy N kinds of goods from savages, and each kind of goods has a price in gold coins. Columbus brought enough glass beads with him, because he knew that for savages, a glass bead is as valuable as a gold coin. Columbus could buy an item he need only in four ways below:
1. Pay the price all by gold coins.
2. Pay by ONE glass bead and some gold coins. In this way, if an item’s price is k gold coins, Columbus could just pay k � 1 gold coins and one glass bead.
3. Pay by an item which has the same price.
4. Pay by a cheaper item and some gold coins.
Columbus found out an interesting thing in the trade rule of savages: For some kinds of goods, when the buyer wanted to buy an item by paying a cheaper item and some gold coins, he didn’t have to pay the price difference, he can pay less. If one could buy an item of kind A by paying a cheaper item of kind B plus some gold coins less than the price difference between B and A, Columbus called that there was a “bargain” between kind B and kind A. To get an item, Columbus didn’t have to spend gold coins as many as its price because he could use glass beads or took full advantages of “bargains”. So Columbus wanted to know, for any kind of goods, at least how many gold coins he had to spend in order to get one � Columbus called it “actual price” of that kind of goods.
Just for curiosity, Columbus also wanted to know, how many kinds of goods are there whose “actual price” was equal to the sum of “actual price” of other two kinds.
输入:
The first line in the input is an integer T indicating the number of test cases ( 0 < T <= 10).
For each test case:
The first line contains an integer N, meaning there are N kinds of goods ( 0 < N <= 20). These N kinds are numbered from 1 to N.
Then N lines follow, each contains two integers Q and P, meaning that the price of the goods of kind Q is P. ( 0 <Q <=N, 0 < P <= 30 )
The next line is a integer M( 0 < M <= 20 ), meaning there are M “bargains”.
Then M lines follow, each contains three integers N1, N2 and R, meaning that you can get an item of kind N2 by paying an item of kind N1 plus R gold coins. It’s guaranteed that the goods of kind N1 is cheaper than the goods of kind N2 and R is none negative and less than the price difference between the goods of kind N2 and kind N1. Please note that R could be zero.
输出:
The first line in the input is an integer T indicating the number of test cases ( 0 < T <= 10).
For each test case:
The first line contains an integer N, meaning there are N kinds of goods ( 0 < N <= 20). These N kinds are numbered from 1 to N.
Then N lines follow, each contains two integers Q and P, meaning that the price of the goods of kind Q is P. ( 0 <Q <=N, 0 < P <= 30 )
The next line is a integer M( 0 < M <= 20 ), meaning there are M “bargains”.
Then M lines follow, each contains three integers N1, N2 and R, meaning that you can get an item of kind N2 by paying an item of kind N1 plus R gold coins. It’s guaranteed that the goods of kind N1 is cheaper than the goods of kind N2 and R is none negative and less than the price difference between the goods of kind N2 and kind N1. Please note that R could be zero.
样例输入:
1 4 1 4 2 9 3 5 4 13 2 1 2 3 3 4 6
样例输出:
1 3 2 6 3 4 4 10 1
题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=3268
这是一个最短路的问题，建立一个源点S，然后连接所有的点，边上的权值为最初的价钱p-1，可用来交易的物品建边，权值为R，然后价钱相等的物品建边，权值为0,求以S为源点的单源多点最短路，即可求出结果，第二问三重循环可求解，注意第二问循环的判断条件，勿让物品选重复。。。，这里wa了好久。。代码参考：
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; #define CLR(arr,v) memset(arr,v,sizeof(arr)) int m,n; const int size = 50; const int INS = INT_MAX/2; int val[size],dis[size]; int h[size],ed[1000],nex[1000],price[1000],que[size],inque[size]; int pos,head,total; void init() { pos = 1;head = total = 0; CLR(h,0); CLR(que,0); CLR(price,0); CLR(ed,0);CLR(inque,0);CLR(nex,0); fill(dis,dis+size,INS);CLR(val,0); } void add(int u,int v,int f) { ed[pos] = v; price[pos] = f; nex[pos] = h[u]; h[u] = pos++; } void SPFA() { dis[0] = 0; que[total++] = 0; inque[0] = true; while(head < total) { int p = que[head]; inque[p] = false; head = (head+1)%size; for(int i = h[p]; i ;i = nex[i]) { int to = ed[i]; if(dis[to] > dis[p] + price[i]) { dis[to] = dis[p] + price[i]; if(!inque[to]) { que[total] = to; inque[to] = true; total = (total+1)%size; } } } } for(int i = 1;i <= n;++i) { printf("%d %d\n",i,dis[i]); } int cnt = 0; CLR(val,0); for(int i = 1;i <= n;++i) for(int j = 1;j <= n;++j) for(int k = 1 + j;k <= n;++k) if(i != j && i != k && dis[i] == dis[k] + dis[j] && !val[i]) { val[i] = true;cnt++; } printf("%d\n",cnt); } int main() { int T; scanf("%d",&T); while(T--) { init(); scanf("%d",&n); int b,money; for(int i = 1;i <= n;++i) { scanf("%d%d",&b,&money); val[b] = money; add(0,b,money-1); } scanf("%d",&m); int u,v,f; for(int i = 0;i < m;++i) { scanf("%d%d%d",&u,&v,&f); add(u,v,f); } for(int i = 1;i <= n;++i) for(int j = 1;j <= n;++j) if(i != j && val[i] == val[j]) { add(i,j,0); add(j,i,0); } SPFA(); } return 0; }
参考：http://blog.csdn.net/fire__ice/article/details/7353430
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
兵1:蛤！
分三种情况讨论。Not Possible就是impossible
排版
6题应该就是算概率的吧
目前为止见过的最易懂的一个，多谢分享
第一种方法怎么会是O(log(m+n))呢？没有二分的话直接遍历应该就是O(m+n)吧？
先从简单的做起，归并排序，二叉树相关的遍历等
有没有C++语言的代码？
顶一个 赞一个
真心不错，力顶作者
涨姿势了
https://coding.net/moon/miracle
这是研发类的题还是算法类？
很棒的网站，加油！⛽


You need to provide the app with the index of the first and last page of your AO3 history for the year that you specified. If you want a summary of the fics that you read in 2020, you need to click through the pages of your AO3 history to find a) the page that contains the last fic that you read in 2020 (this is the start page), and b) the page that contains the first fic that you read in 2020 (this is the end page). The app will only look at the pages in this range.
For example, if the first 5 pages of your history are all fics that you read in 2021, and your 2020 history starts on page 6, you should type 6 in the "Start Page" field. If your 2020 history continues for 15 pages and the last page that contains a fic you read in 2020 is on page 21, then type 21 in the "End Page" field.
In order to keep wait times low for all users, you cannot retrieve more than 200 pages of history at a time. If your history for a particular year spans more than 200 pages, then you can try splitting it up into multiple chunks, which will give you a different summary result for each chunk (you can manually combine the output spreadsheet yourself if you want). So for example, if your 2020 history starts on page 4 and ends on page 306, you could run the app once with Start Page = 4 and End Page = 150, and again with Start Page = 151 and End Page = 306.
Return to main page


| repetitions = number of shifts to make right |
|
This performs a right binary shift on the value the specified number of times. This basically is a faster method of dividing the value exponentially. By shifting right once, you are dividing the value by 2. By shifting right twice, you divide by 4, etc.
Sar command varies from Shr whereas it fills blank bits shifted with copies of the sign bit, 0 for positive numbers and 1 for negative. The usefulness of this command is basically faster math execution. Also see Shl. See also: Shl, Shr. |
|
; shl, shr, sar examples
value = 100 ; multiple x 2 Print "Shift 1 bit left; Value = " + value Shl 1 ; multiple x 4 Print "Shift 2 bits left; Value = " + value Shl 2 ; multiple x 16 Print "Shift 4 bits left; Value = " + value Shl 4 ; divide by 2 Print "Shift 1 bit right; Value = " + value Shr 1 ; divide by 4 Print "Shift 2 bits right; Value = " + value Shr 2 ; divide by 16 Print "Shift 4 bits right; Value = " + value Shr 4 Print "Shift by SAR 4 times = " + value Sar 4 WaitKey() |


I'm a full stack developer currently seeking new opportunities. Take a look through my projects, get to know me, and check out my resume.
Feel free to contact me by phone, email, mail, or LinkedIn.
Thanks for stopping by!
Presumably you've come to this page to learn a little more about me. Thank you! That's very kind.
I was born in the sunny town of Calabasas, California in the spring of 1993, a strangely excellent year in film. I had an eventful childhood that I will save for my memoirs - all I'll say now is that I was surrounded by a loving and supporting family and an inspiring group of friends, teachers, and mentors, for whom I am very grateful.
I made my way to New York in 2011 to attend New York University's Tisch School of the Arts for acting, where I graduated with honors. In my final semester there I took my first web design class and fell deeply in love with code and design. After graduating NYU, I attended Dev Bootcamp in New York City's Financial District, and I am now seeking employment as a junior developer.
For fun, I like to comb the city for cool music venues, themed bars, and cult film events. I also see a lot of comedy shows, and I still write and perform comedy as a hobby.


This transformation class implements a randomizing displacement. The scaling of the randomization can be controlled from the Disturbance property. The effect of the transformation is visualized in the following image:
[See Also]


Preparation time
1-2 hours
Cooking time
10 to 30 mins
Serves
Makes 36 breadsticks
Dietary
These pencil-thin sticks studded with green olives are great served with olive oil or your favourite dips for a party.
Equipment and preparation: You will need a mixer fitted with a dough hook.
Oil two 2-3 litre/3½-5¼ pints square plastic container.
Put the flour into the bowl of a mixer fitted with a dough hook. Add the salt to one side of the bowl and the yeast to the other. Add three-quarters of the water and begin mixing on a slow speed. As the dough starts to come together, gradually add the remaining water.
Mix for a further 5-8 minutes on a medium speed. The dough should now be wet and stretch easily when pulled. Add the olive oil and mix for a further two minutes. Add the olives and mix until well-distributed.
Put the dough into the oiled containers and leave until they have at least tripled in size – for approximately an hour.
Line four baking trays with baking parchment or silicone paper and preheat the oven to 220C/425F/Gas 7.
Dust the work surface heavily with flour – add some semolina too, if you have some. Carefully tip the dough onto the surface. It will be very loose and flowing – but don’t worry. Rather than knocking it back, handle it gently so that you keep as much air in the dough as possible.
Dust the top of the dough with flour and then stretch it out gently to a rough rectangle. Starting at one long edge, cut the dough into approximately 36 strips. Stretch each piece out until 20-25cm/8-10in long. Place six strips onto each of the prepared baking trays, spacing them apart.
Bake the dough sticks for 10-15 minutes. Cool on wire rack.


url-signer
Tiny library for signing and validating URLs. Also exposes an Express middleware which is optional to use.
Usage
Initializing the singleton
var signer = require('url-signer');
signer.init({
privateKey: "mySuperSecurePrivateKey", // required
algorithm: "sha256", // optional
digest: "base64", // optional
ttl: 3600 // optional
});
Signing a URL
var signedUrl = signer.getSignedUrl("http://site.com?id=50&accessToken=ae75ofjb7402");
Validating a URL
var valid = signer.verifySignedUrl(signedUrl);
if (valid === true) {
// all good; serve the secure payload
} else if (valid === 'expired') {
// the signed url was valid but has been expired
} else{
// the signed url is invalid
}
Using the Express middleware
// Using the default behavior of `signer.verifier()`
// Sends 403 if invalid
// Sends 410 if expired
app.get("/endpoint", signer.verifier(), function(req,res) {
// all good!
// res.sendStatus(200);
});
// Using the custom callbacks with `signer.verifier()`
app.get("/endpoint", signer.verifier({
invalid: function(req, res) {
// req.sendStatus(403);
},
expired: function(req, res) {
// req.sendStatus(410);
}
}), function(req,res) {
// all good!
// res.sendStatus(200);
});
History
v0.1.0
Initial release
License
The MIT License (MIT)
Copyright (c) 2014 Kamil Waheed
Permission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the "Software"), to deal in the Software without restriction, including without limitation the rights to use, copy, modify, merge, publish, distribute, sublicense, and/or sell copies of the Software, and to permit persons to whom the Software is furnished to do so, subject to the following conditions:
The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software.
 IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.


EVO HTML to PDF Converter allows you to add watermarks and stamps to generated PDF document. You can add any PDF element in a watermark or a stamp repeatead in each PDF page, including HTML.
The following options are available in this demo:
-
HTML Page URL or Local File to Convert. The URL of the HTML page to convert must be accessible from the computer where the converter runs. If the page requires authentication or if you are using a proxy server to access Internet
then you have to set the converter properties accordingly as described in documentation
-
Stamp Size in PDF Page. You can set the stamp width and height in points, 1 point is 1/72 of an inch
-
Stamp HTML Code. The HTML string to be rendered in the stamp. Optionally you can also set a base URL to be used to resolve the relative resources URLs to full URLs


Henry Golding’s Last Christmas Movie Is Number 1 In UK, Even Surpasses JOKER
by Thermesh VelusamyTap to listen to this article instead: 🔊 Listen to Post
Malaysians have always been making us proud. But this Malaysian has only shone brighter and brighter since he first burst into the public eye as part of the iconic 8TV Quickie crew. Yes, it’s Henry Golding!
First, he was in one of the biggest movies of 2018, Crazy Rich Asians, then he was named as one of Top 100 Most Handsome Faces of 2019. In case you’ve been in a cave somewhere, his latest movie, Last Christmas, was just released – and he stars alongside Emilia Clarke of Game of Thrones fame and his Crazy Rich Asians co-star Michelle Yeoh.
So, good news! Last Christmas has officially become the #1 movie in UK last weekend! It even managed to outrank Joker, according to Screen Daily. Bad news for Joker fans though!
The movie made £2.6 million (RM14 million) on its opening weekend, and Malaysians were pretty proud of Henry Golding. Compliments have been rolling in on Twitter, praising Henry Golding on his performance in the movie.
MALAYSIA BOLEH!
It’s definitely a proud day for Henry Golding, and we as Malaysians can’t help but tumpang in the pride. Here’s to wishing Henry Golding the best in his thriving film career!
Also read: Our Homeboy, Henry Golding Becomes Only M’sian To Make It Into TIME’s 100 Next List


where I learned a lot of things. There are a lot of experiences yet to be have but in just 3 years of
studying there, I learned so much not only about studies, but also about life.
Real projects. Real
learning.
I've spent so many years to practice and harness my talents
I used to play bass guitar in our band - IndieWorld.
-
-
-
You can contact me at the following:
Why would I give my address, right?


| Top |
| GtkToolItem * | gtk_tool_button_new () |
| GtkToolItem * | gtk_tool_button_new_from_stock () |
| void | gtk_tool_button_set_label () |
| const gchar * | gtk_tool_button_get_label () |
| void | gtk_tool_button_set_use_underline () |
| gboolean | gtk_tool_button_get_use_underline () |
| void | gtk_tool_button_set_stock_id () |
| const gchar * | gtk_tool_button_get_stock_id () |
| void | gtk_tool_button_set_icon_name () |
| const gchar * | gtk_tool_button_get_icon_name () |
| void | gtk_tool_button_set_icon_widget () |
| GtkWidget * | gtk_tool_button_get_icon_widget () |
| void | gtk_tool_button_set_label_widget () |
| GtkWidget * | gtk_tool_button_get_label_widget () |
| gchar * | icon-name | Read / Write |
| GtkWidget * | icon-widget | Read / Write |
| gchar * | label | Read / Write |
| GtkWidget * | label-widget | Read / Write |
| gchar * | stock-id | Read / Write |
| gboolean | use-underline | Read / Write |
GObject ╰── GInitiallyUnowned ╰── GtkWidget ╰── GtkContainer ╰── GtkBin ╰── GtkToolItem ╰── GtkToolButton ├── GtkMenuToolButton ╰── GtkToggleToolButton
GtkToolButton implements AtkImplementorIface, GtkBuildable, GtkActivatable and GtkActionable.
GtkToolButtons are GtkToolItems containing buttons.
Use gtk_tool_button_new()
to create a new GtkToolButton.
The label of a GtkToolButton is determined by the properties
“label-widget”, “label”, and
“stock-id”. If “label-widget” is
non-NULL
, then that widget is used as the label. Otherwise, if
“label” is non-NULL
, that string is used as the label.
Otherwise, if “stock-id” is non-NULL
, the label is
determined by the stock item. Otherwise, the button does not have a label.
The icon of a GtkToolButton is determined by the properties
“icon-widget” and “stock-id”. If
“icon-widget” is non-NULL
, then
that widget is used as the icon. Otherwise, if “stock-id” is
non-NULL
, the icon is determined by the stock item. Otherwise,
the button does not have a icon.
GtkToolItem * gtk_tool_button_new (GtkWidget *icon_widget
,const gchar *label
);
Creates a new GtkToolButton using icon_widget
as contents and label
as
label.
Since: 2.4
GtkToolItem *
gtk_tool_button_new_from_stock (const gchar *stock_id
);
gtk_tool_button_new_from_stock
has been deprecated since version 3.10 and should not be used in newly-written code.
Use gtk_tool_button_new()
together with
gtk_image_new_from_icon_name()
instead.
Creates a new GtkToolButton containing the image and text from a stock item. Some stock ids have preprocessor macros like GTK_STOCK_OK and GTK_STOCK_APPLY.
It is an error if stock_id
is not a name of a stock item.
Since: 2.4
void gtk_tool_button_set_label (GtkToolButton *button
,const gchar *label
);
Sets label
as the label used for the tool button. The “label”
property only has an effect if not overridden by a non-NULL
“label-widget” property. If both the “label-widget”
and “label” properties are NULL
, the label is determined by the
“stock-id” property. If the “stock-id” property is
also NULL
, button
will not have a label.
Since: 2.4
const gchar *
gtk_tool_button_get_label (GtkToolButton *button
);
Returns the label used by the tool button, or NULL
if the tool button
doesn’t have a label. or uses a the label from a stock item. The returned
string is owned by GTK+, and must not be modified or freed.
Since: 2.4
void gtk_tool_button_set_use_underline (GtkToolButton *button
,gboolean use_underline
);
If set, an underline in the label property indicates that the next character
should be used for the mnemonic accelerator key in the overflow menu. For
example, if the label property is “_Open” and use_underline
is TRUE
,
the label on the tool button will be “Open” and the item on the overflow
menu will have an underlined “O”.
Labels shown on tool buttons never have mnemonics on them; this property only affects the menu item on the overflow menu.
Since: 2.4
gboolean
gtk_tool_button_get_use_underline (GtkToolButton *button
);
Returns whether underscores in the label property are used as mnemonics
on menu items on the overflow menu. See gtk_tool_button_set_use_underline()
.
TRUE
if underscores in the label property are used as
mnemonics on menu items on the overflow menu.
Since: 2.4
void gtk_tool_button_set_stock_id (GtkToolButton *button
,const gchar *stock_id
);
gtk_tool_button_set_stock_id
has been deprecated since version 3.10 and should not be used in newly-written code.
Use gtk_tool_button_set_icon_name()
instead.
Sets the name of the stock item. See gtk_tool_button_new_from_stock()
.
The stock_id property only has an effect if not overridden by non-NULL
“label-widget” and “icon-widget” properties.
Since: 2.4
const gchar *
gtk_tool_button_get_stock_id (GtkToolButton *button
);
gtk_tool_button_get_stock_id
has been deprecated since version 3.10 and should not be used in newly-written code.
Use gtk_tool_button_get_icon_name()
instead.
Returns the name of the stock item. See gtk_tool_button_set_stock_id()
.
The returned string is owned by GTK+ and must not be freed or modifed.
Since: 2.4
void gtk_tool_button_set_icon_name (GtkToolButton *button
,const gchar *icon_name
);
Sets the icon for the tool button from a named themed icon.
See the docs for GtkIconTheme for more details.
The “icon-name” property only has an effect if not
overridden by non-NULL
“label-widget”,
“icon-widget” and “stock-id” properties.
Since: 2.8
const gchar *
gtk_tool_button_get_icon_name (GtkToolButton *button
);
Returns the name of the themed icon for the tool button,
see gtk_tool_button_set_icon_name()
.
Since: 2.8
void gtk_tool_button_set_icon_widget (GtkToolButton *button
,GtkWidget *icon_widget
);
Sets icon
as the widget used as icon on button
. If icon_widget
is
NULL
the icon is determined by the “stock-id” property. If the
“stock-id” property is also NULL
, button
will not have an icon.
Since: 2.4
GtkWidget *
gtk_tool_button_get_icon_widget (GtkToolButton *button
);
Return the widget used as icon widget on button
.
See gtk_tool_button_set_icon_widget()
.
Since: 2.4
void gtk_tool_button_set_label_widget (GtkToolButton *button
,GtkWidget *label_widget
);
Sets label_widget
as the widget that will be used as the label
for button
. If label_widget
is NULL
the “label” property is used
as label. If “label” is also NULL
, the label in the stock item
determined by the “stock-id” property is used as label. If
“stock-id” is also NULL
, button
does not have a label.
Since: 2.4
GtkWidget *
gtk_tool_button_get_label_widget (GtkToolButton *button
);
Returns the widget used as label on button
.
See gtk_tool_button_set_label_widget()
.
Since: 2.4
struct GtkToolButtonClass { GtkToolItemClass parent_class; GType button_type; /* signal */ void (* clicked) (GtkToolButton *tool_item); };
GType |
||
Signal emitted when the tool button is clicked with the mouse or activated with the keyboard. |
“icon-name”
property“icon-name” gchar *
The name of the themed icon displayed on the item. This property only has an effect if not overridden by “label-widget”, “icon-widget” or “stock-id” properties.
Flags: Read / Write
Default value: NULL
Since: 2.8
“icon-widget”
property“icon-widget” GtkWidget *
Icon widget to display in the item.
Flags: Read / Write
“label”
property“label” gchar *
Text to show in the item.
Flags: Read / Write
Default value: NULL
“label-widget”
property“label-widget” GtkWidget *
Widget to use as the item label.
Flags: Read / Write
“stock-id”
property“stock-id” gchar *
The stock icon displayed on the item.
GtkToolButton:stock-id
has been deprecated since version 3.10 and should not be used in newly-written code.
Use “icon-name” instead.
Flags: Read / Write
Default value: NULL
“use-underline”
property“use-underline” gboolean
If set, an underline in the label property indicates that the next character should be used for the mnemonic accelerator key in the overflow menu.
Flags: Read / Write
Default value: FALSE
“icon-spacing”
style property“icon-spacing” gint
Spacing in pixels between the icon and label.
Flags: Read / Write
Allowed values: >= 0
Default value: 3
“clicked”
signalvoid user_function (GtkToolButton *toolbutton, gpointer user_data)
This signal is emitted when the tool button is clicked with the mouse or activated with the keyboard.
toolbutton |
the object that emitted the signal |
|
user_data |
user data set when the signal handler was connected. |
Flags: Action