"""simple docstring"""






from __future__ import annotations

from math import gcd



def 						a_		(      lowerCamelCase      ,    lowerCamelCase = 2      ,    lowerCamelCase = 1      ,    lowerCamelCase = 3      ,    ):
				# A value less than 2 can cause an infinite loop in the algorithm.
				if num < 2:
								raise ValueError('The input value cannot be less than 2' )

				# Because of the relationship between ``f(f(x))`` and ``f(x)``, this
				# algorithm struggles to find factors that are divisible by two.
				# As a workaround, we specifically check for two and even inputs.
				#   See: https://math.stackexchange.com/a/2856214/165820
				if num > 2 and num % 2 == 0:
								return 2

				# Pollard's Rho algorithm requires a function that returns pseudorandom
				# values between 0 <= X < ``num``.  It doesn't need to be random in the
				# sense that the output value is cryptographically secure or difficult
				# to calculate, it only needs to be random in the sense that all output
				# values should be equally likely to appear.
				# For this reason, Pollard suggested using ``f(x) = (x**2 - 1) % num``
				# However, the success of Pollard's algorithm isn't guaranteed and is
				# determined in part by the initial seed and the chosen random function.
				# To make retries easier, we will instead use ``f(x) = (x**2 + C) % num``
				# where ``C`` is a value that we can modify between each attempt.
				def rand_fn(lowerCamelCase      ,    lowerCamelCase      ,    lowerCamelCase ) -> int:
								return (pow(lowerCamelCase      ,    2 ) + step) % modulus

				for _ in range(lowerCamelCase ):
								# These track the position within the cycle detection logic.
								UpperCAmelCase__    =							seed
								UpperCAmelCase__    =							seed

								while True:
												# At each iteration, the tortoise moves one step and the hare moves two.
												UpperCAmelCase__    =							rand_fn(lowerCamelCase      ,    lowerCamelCase      ,    lowerCamelCase )
												UpperCAmelCase__    =							rand_fn(lowerCamelCase      ,    lowerCamelCase      ,    lowerCamelCase )
												UpperCAmelCase__    =							rand_fn(lowerCamelCase      ,    lowerCamelCase      ,    lowerCamelCase )

												# At some point both the tortoise and the hare will enter a cycle whose
												# length ``p`` is a divisor of ``num``.  Once in that cycle, at some point
												# the tortoise and hare will end up on the same value modulo ``p``.
												# We can detect when this happens because the position difference between
												# the tortoise and the hare will share a common divisor with ``num``.
												UpperCAmelCase__    =							gcd(hare - tortoise      ,    lowerCamelCase )

												if divisor == 1:
																# No common divisor yet, just keep searching.
																continue
												else:
																# We found a common divisor!
																if divisor == num:
																				# Unfortunately, the divisor is ``num`` itself and is useless.
																				break
																else:
																				# The divisor is a nontrivial factor of ``num``!
																				return divisor

        # If we made it here, then this attempt failed.
        # We need to pick a new starting seed for the tortoise and hare
        # in addition to a new step value for the random function.
        # To keep this example implementation deterministic, the
        # new values will be generated based on currently available
        # values instead of using something like ``random.randint``.

        # We can use the hare's position as the new seed.
        # This is actually what Richard Brent's the "optimized" variant does.
								UpperCAmelCase__    =							hare

								# The new step value for the random function can just be incremented.
								# At first the results will be similar to what the old function would
								# have produced, but the value will quickly diverge after a bit.
								step += 1

				# We haven't found a divisor within the requested number of attempts.
				# We were unlucky or ``num`` itself is actually prime.
				return None


if __name__ == "__main__":
						import argparse

						lowerCAmelCase__						:						int		  =			argparse.ArgumentParser()
						parser.add_argument(
						    'num',
						    type=int,
						    help='The value to find a divisor of',
						)
						parser.add_argument(
						    '--attempts',
						    type=int,
						    default=3,
						    help='The number of attempts before giving up',
						)
						lowerCAmelCase__						:						Optional[Any]		  =			parser.parse_args()

						lowerCAmelCase__						:						Tuple		  =			pollard_rho(args.num, attempts=args.attempts)
						if divisor is None:
												print(F"""{args.num} is probably prime""")
						else:
												lowerCAmelCase__						:						Tuple		  =			args.num // divisor
												print(F"""{args.num} = {divisor} * {quotient}""")






"""simple docstring"""






import random
class        snake_case :




					"""simple docstring"""

					@staticmethod
					def 	__lowerCAmelCase		(       lowerCamelCase__     :			str    ):
									UpperCAmelCase__    =							[ord(lowerCamelCase__    ) for i in text]
									UpperCAmelCase__    =							[]
									UpperCAmelCase__    =							[]
									for i in plain:
													UpperCAmelCase__    =							random.randint(1					,300    )
													UpperCAmelCase__    =							(i + k) * k
													cipher.append(lowerCamelCase__    )
													key.append(lowerCamelCase__    )
									return cipher, key







					@staticmethod
					def 	__lowerCAmelCase		(       lowerCamelCase__     :			list[int]					,lowerCamelCase__     :			list[int]    ):
									UpperCAmelCase__    =							[]
									for i in range(len(lowerCamelCase__    )    ):
													UpperCAmelCase__    =							int((cipher[i] - (key[i]) ** 2) / key[i]    )
													plain.append(chr(lowerCamelCase__    )    )
									return "".join(lowerCamelCase__    )


if __name__ == "__main__":
						lowerCAmelCase__  ,			lowerCAmelCase__						:						Dict		  =			Onepad().encrypt('Hello')
						print(c, k)
						print(Onepad().decrypt(c, k))



